身份证,组织机构,营业执照号检验函数

以下代码由PHP站长网 52php.cn收集自互联网

现在PHP站长网小编把它分享给大家，仅供参考

GO
/****** Object:  UserDefinedFunction [ro].[wj_ValidateIDC]    Script Date: 09/29/2012 11:23:34 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
--验证身份证号码
--编者：
--创建日期：2012-09-18
--参数：@idc 身份证号
create FUNCTION [ro].[wj_ValidateIDC]
(
 @idc varchar(18)
)RETURNS BIT
AS
BEGIN

 DECLARE @validFactors VARCHAR(17),@validCodes VARCHAR(11),@i TINYINT,@iTemp INT
 SELECT @validFactors='79A584216379A5842',@validCodes='10X98765432',@i=1,@iTemp=0
 --验证校验位
 --根据担保数据库增加条件，否则报错，by WJ
 IF (@idc LIKE 'x%' OR @idc LIKE '*%' OR @idc LIKE 'T%')
    RETURN(0) 
 IF LEN(@idc)<>15 AND LEN(@idc)<>18--身份证号只有15或18位
  RETURN(0)
 IF LEN(@idc)=15  --如果是15位身份证 则只验证日期
     IF (ISDATE('19'+SUBSTRING(@idc,7,6))=0 and '19'+SUBSTRING(@idc,6) between '1900-01-01' and '2010-01-01')
        RETURN(0)
     ELSE
        RETURN(1)
 --18位身份证 验证日期 校验位
 IF (ISDATE(SUBSTRING(@idc,8))=0 and SUBSTRING(@idc,6) between '1900-01-01' and '2010-01-01')--验证日期
    RETURN(0)
 ---验证校验位开始
 
 WHILE @i<18
    BEGIN
       SELECT @[email?protected]+CAST(SUBSTRING(@idc,@i,1) AS INT)*
             (CASE SUBSTRING(@validFactors,1) WHEN 'A' THEN 10 ELSE SUBSTRING(@validFactors,1) END),@[email?protected]+1
    END
 IF SUBSTRING(@validCodes,@iTemp%11+1,1)=RIGHT(@idc,1)
    RETURN 1
 ELSE
    RETURN 0
 RETURN 0
END


GO
/****** Object:  UserDefinedFunction [ro].[wj_ValidateYYZZNo]    Script Date: 09/29/2012 11:25:49 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
--功能：验证营业执照号
--编者：
--创建日期：2012-09-20
--参数：@ZzNo 营业执照号
create FUNCTION [ro].[wj_ValidateYYZZNo]
(
 @ZzNo varchar(15)
)RETURNS BIT
AS
BEGIN

 DECLARE @m INT,@n INT,@s INT,@p INT,@i INT,@result INT 
 SELECT @m=10,@n=11,@[email?protected]
 
 IF (LEN(LTRIM(RTRIM(@ZzNo)))=13 AND ISNUMERIC(@ZzNo) =1) 
 begin
 RETURN 1
 END 
 IF (ISNUMERIC(LTRIM(RTRIM(@ZzNo)))=0) 
 begin
 RETURN 0
 end
 IF (LEN(LTRIM(RTRIM(@ZzNo)))<>15) 
 begin
 RETURN 0
 END
 
 SET @i=1
 WHILE @i <=14
 BEGIN 
 SET @s = SUBSTRING(@ZzNo,1)
 SET @p = @[email?protected]
 SET @p [email?protected]%@m
 IF @p = 0
 BEGIN
    SET @p= @m
 END 
 SET @p = @p *2 
 SET @p = @p%@n
 SET @[email?protected]+1
 END 
 SET @p = @p+SUBSTRING(@ZzNo,15,1)
 SET @p = @p%@m
 
 IF @p=1 
    BEGIN
    SET @result =1
    END 
    ELSE 
    BEGIN
    SET @result =0
    end
RETURN @result
END

GO
/****** Object:  UserDefinedFunction [ro].[wj_ValidateZZJGNo]    Script Date: 09/29/2012 11:26:32 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
--功能：组织机构号验证
--编者：
--创建日期：2012-09-20
--参数：@ZZJGNo 组织机构号
ALTER FUNCTION [ro].[wj_ValidateZZJGNo]
(
 @ZZJGNo varchar(20)
)RETURNS BIT
AS
BEGIN
DECLARE @c varchar(20),@zz int,@z int,@jaz VARCHAR(30),@C9 VARCHAR(10)
SET @ZZJGNo = UPPER(@ZZJGNo)

SET @i=1
WHILE @i <=8
BEGIN
SET @c= SUBSTRING(@ZZJGNo,1)
IF @c>='A' AND @c<='Z'
BEGIN
  SET @z = (ASCII(@c)-55) * (CASE @i WHEN 1 THEN 3 WHEN 2 THEN 7 WHEN 3 THEN 9 WHEN 4 THEN 10 WHEN 5 THEN 5 WHEN 6 THEN 8 WHEN 7 THEN 4 WHEN 8 THEN 2 END)
END 
ELSE IF @c>='0' AND @c<='9' 
BEGIN
  SET @z=CONVERT(NUMERIC,@c) * (CASE @i WHEN 1 THEN 3 WHEN 2 THEN 7 WHEN 3 THEN 9 WHEN 4 THEN 10 WHEN 5 THEN 5 WHEN 6 THEN 8 WHEN 7 THEN 4 WHEN 8 THEN 2 END)

END
ELSE
BEGIN
RETURN 0
END  
SET @zz = ISNULL(@zz,0)[email?protected] 
SET @i = @i+1
END


SET @jaz = 11-(@zz%11)
IF @jaz=10
BEGIN
SET @C9 = 'X'
END 
ELSE IF @jaz =11
BEGIN
SET @C9='0'    
END
ELSE 
BEGIN
SET @C9=LTRIM(RTRIM(@jaz))
END 


IF @ZZJGNO = SUBSTRING(@ZZJGNO,1,8) [email?protected]
BEGIN
    RETURN 1 
END 
IF @ZZJGNO = SUBSTRING(@ZZJGNO,8)+'-'[email?protected]
BEGIN
    RETURN 1
END
IF @ZZJGNO = SUBSTRING(@ZZJGNO,8) + '—' [email?protected]
BEGIN
    RETURN 1
END
IF @ZZJGNO = SUBSTRING(@ZZJGNO,8) +' '[email?protected]
BEGIN
    RETURN 1 
END 
 RETURN 0
END

以上内容由PHP站长网【52php.cn】收集整理供大家参考研究

如果以上内容对您有帮助，欢迎收藏、点赞、推荐、分享。

（编辑：ASP站长网）